It’s trivial to use a web form which is made by HTML code for uploading files from web browser to a server. This is commonly referred as form based file upload, and typically suitable for web-based applications. How about standalone or command line-based applications – which sometimes need to upload files to a web server but cannot use an upload form in HTML? Well, this article is going to answer that question by implementing the following solution:
We can call this method as non-form based file upload. Keep in mind that, this is not FTP upload, because it is still using HTTP protocol for transmitting the file.
Let’s examine how each part is implemented.
Write a Java servlet as follows:
package net.codejava.servlet; import java.io.File; import java.io.FileOutputStream; import java.io.IOException; import java.io.InputStream; import java.util.Enumeration; import javax.servlet.ServletException; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; /** * This servlet demonstrates how to receive file uploaded from the client * without using third-party upload library such as Commons File Upload. * @author www.codejava.net */ public class ReceiveFileServlet extends HttpServlet { static final String SAVE_DIR = "E:/Test/Upload/"; static final int BUFFER_SIZE = 4096; protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { // Gets file name for HTTP header String fileName = request.getHeader("fileName"); File saveFile = new File(SAVE_DIR + fileName); // prints out all header values System.out.println("===== Begin headers ====="); Enumeration<String> names = request.getHeaderNames(); while (names.hasMoreElements()) { String headerName = names.nextElement(); System.out.println(headerName + " = " + request.getHeader(headerName)); } System.out.println("===== End headers =====\n"); // opens input stream of the request for reading data InputStream inputStream = request.getInputStream(); // opens an output stream for writing file FileOutputStream outputStream = new FileOutputStream(saveFile); byte[] buffer = new byte[BUFFER_SIZE]; int bytesRead = -1; System.out.println("Receiving data..."); while ((bytesRead = inputStream.read(buffer)) != -1) { outputStream.write(buffer, 0, bytesRead); } System.out.println("Data received."); outputStream.close(); inputStream.close(); System.out.println("File written to: " + saveFile.getAbsolutePath()); // sends response to client response.getWriter().print("UPLOAD DONE"); } }
This servlet handles HTTP POST requests in its doPost()method. There are some important points here in this code:
Now let’s examine how the client is implemented.
Following is code of the client program:
import java.io.BufferedReader; import java.io.File; import java.io.FileInputStream; import java.io.IOException; import java.io.InputStreamReader; import java.io.OutputStream; import java.net.HttpURLConnection; import java.net.URL; /** * This program demonstrates how to upload files to a web server * using HTTP POST request without any HTML form. * @author www.codejava.net * */ public class NonFormFileUploader { static final String UPLOAD_URL = "http://localhost:8080/CodeWeb/ReceiveFileServlet"; static final int BUFFER_SIZE = 4096; public static void main(String[] args) throws IOException { // takes file path from first program's argument String filePath = args[0]; File uploadFile = new File(filePath); System.out.println("File to upload: " + filePath); // creates a HTTP connection URL url = new URL(UPLOAD_URL); HttpURLConnection httpConn = (HttpURLConnection) url.openConnection(); httpConn.setUseCaches(false); httpConn.setDoOutput(true); httpConn.setRequestMethod("POST"); // sets file name as a HTTP header httpConn.setRequestProperty("fileName", uploadFile.getName()); // opens output stream of the HTTP connection for writing data OutputStream outputStream = httpConn.getOutputStream(); // Opens input stream of the file for reading data FileInputStream inputStream = new FileInputStream(uploadFile); byte[] buffer = new byte[BUFFER_SIZE]; int bytesRead = -1; System.out.println("Start writing data..."); while ((bytesRead = inputStream.read(buffer)) != -1) { outputStream.write(buffer, 0, bytesRead); } System.out.println("Data was written."); outputStream.close(); inputStream.close(); // always check HTTP response code from server int responseCode = httpConn.getResponseCode(); if (responseCode == HttpURLConnection.HTTP_OK) { // reads server's response BufferedReader reader = new BufferedReader(new InputStreamReader( httpConn.getInputStream())); String response = reader.readLine(); System.out.println("Server's response: " + response); } else { System.out.println("Server returned non-OK code: " + responseCode); } } }
The important point here is we use an HttpURLConnection object to send an HTTP POST request to the server at URL of the servlet (identified by the constant UPLOAD_URL) and open the OutputStream of this connection to write byte arrays of the upload file. Path of this file is passed as the first argument of the program.
Similarly to the servlet, we use a while loop to read/write byte arrays from/to the file’s input stream/request’s output stream.
Finally, we read response from the server after closing both input/output streams by using the input stream of the request.
Deploy the ReceiveFileServlet on a servlet container like Tomcat and start the server. Then run the client program by executing the following command:
java NonFormFileUploader e:\Test\RecordAudio.wav
Here we pass a WAV audio file to be uploaded. The server will produce some output as the following screenshot:
From this log, we can examine values of all HTTP headers sent from the client. Almost of values are set by Java automatically, except the filename is set from the client manually.
And here is the output from the client program:
NOTES: