How to extract a zip file in Java programmatically
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- Written by Nam Ha Minh
- Last Updated on 09 August 2020   |   Print Email
- ZipInputStream: this is the main class which can be used for reading zip file and extracting files and directories (entries) within the archive. Here are some important usages of this class:
- read a zip via its constructor ZipInputStream(FileInputStream)
- read entries of files and directories via method getNextEntry()
- read binary data of current entry via method read(byte)
- close current entry via method closeEntry()
- close the zip file via method close()
- ZipEntry: this class represents an entry in the zip file. Each file or directory is represented as a ZipEntry object. Its method getName() returns a String which represents path of the file/directory. The path is in the following form:
folder_1/subfolder_1/subfolder_2/…/subfolder_n/file.ext
- ZipInputStream: this is the main class which can be used for reading zip file and extracting files and directories (entries) within the archive. Here are some important usages of this class:
import java.io.BufferedOutputStream; import java.io.File; import java.io.FileInputStream; import java.io.FileOutputStream; import java.io.IOException; import java.util.zip.ZipEntry; import java.util.zip.ZipInputStream; /** * This utility extracts files and directories of a standard zip file to * a destination directory. * @author www.codejava.net * */ public class UnzipUtility { /** * Size of the buffer to read/write data */ private static final int BUFFER_SIZE = 4096; /** * Extracts a zip file specified by the zipFilePath to a directory specified by * destDirectory (will be created if does not exists) * @param zipFilePath * @param destDirectory * @throws IOException */ public void unzip(String zipFilePath, String destDirectory) throws IOException { File destDir = new File(destDirectory); if (!destDir.exists()) { destDir.mkdir(); } ZipInputStream zipIn = new ZipInputStream(new FileInputStream(zipFilePath)); ZipEntry entry = zipIn.getNextEntry(); // iterates over entries in the zip file while (entry != null) { String filePath = destDirectory + File.separator + entry.getName(); if (!entry.isDirectory()) { // if the entry is a file, extracts it extractFile(zipIn, filePath); } else { // if the entry is a directory, make the directory File dir = new File(filePath); dir.mkdirs(); } zipIn.closeEntry(); entry = zipIn.getNextEntry(); } zipIn.close(); } /** * Extracts a zip entry (file entry) * @param zipIn * @param filePath * @throws IOException */ private void extractFile(ZipInputStream zipIn, String filePath) throws IOException { BufferedOutputStream bos = new BufferedOutputStream(new FileOutputStream(filePath)); byte[] bytesIn = new byte[BUFFER_SIZE]; int read = 0; while ((read = zipIn.read(bytesIn)) != -1) { bos.write(bytesIn, 0, read); } bos.close(); } }The UnzipUtility class has a public method for extracting files and directories from a zip archive:
- unzip(String zipFilePath, String destDirectory): extracts content of a zip file specified by zipFilePath to a directory specified by destDirectory.
/** * A console application that tests the UnzipUtility class * * @author www.codejava.net * */ public class UnzipUtilityTest { public static void main(String[] args) { String zipFilePath = "e:/Test/MyPics.zip"; String destDirectory = "f:/Pics"; UnzipUtility unzipper = new UnzipUtility(); try { unzipper.unzip(zipFilePath, destDirectory); } catch (Exception ex) { // some errors occurred ex.printStackTrace(); } } }
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- How to read contents of a ZIP file in Java
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